Carcass wrote:
In a certain batch of guests in a museum, there are 50 guests; each guest buys either a $40 ticket or a $60 ticket, with at least one guest of each ticket type. The average (arithmetic mean) value of ticket-receipts from the batch is more than $50. If the average value of ticket-receipts is to be reduced to less than $50 by including few new guests with $40 tickets, what could definitely NOT be the number of new guests with $40 tickets that could be included?
A 1
B 2
C 3
D 4
Let's consider the closest and slightly above $50 average. so 24 tickets of $40 and 26 tickets of $60.
To add few tickets of $40 means, the number should of $40 tickets be more than $60 tickets, even one is good enough.
So 26-24 = 2, so there has to be at least 3 tickets.
So it can't be 1 or 2. Answer is A,B.