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A rectangular box with length 6in, width 4in and height 1in has to be
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11 Mar 2022, 00:17
11 Mar 2022, 00:17
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A rectangular box with length 6in, width 4in and height 1in has to be completely wrapped with a single sheet of paper (without any tearing). What could be the dimension of the required paper?
Select all that apply
A. 12in x 4in
B. 12in x 6in
C. 13in x 4in
D. 14in x 5in
E. 15in x 4in
F. 15in x 5in
Select all that apply
A. 12in x 4in
B. 12in x 6in
C. 13in x 4in
D. 14in x 5in
E. 15in x 4in
F. 15in x 5in
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: A rectangular box with length 6in, width 4in and height 1in has to be
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24 Mar 2022, 22:12
24 Mar 2022, 22:12
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KarunMendiratta wrote:
A rectangular box with length 6in, width 4in and height 1in has to be completely wrapped with a single sheet of paper (without any tearing). What could be the dimension of the required paper?
Select all that apply
A. 12in x 4in
B. 12in x 6in
C. 13in x 4in
D. 14in x 5in
E. 15in x 4in
F. 15in x 5in
Select all that apply
A. 12in x 4in
B. 12in x 6in
C. 13in x 4in
D. 14in x 5in
E. 15in x 4in
F. 15in x 5in
Since the box is to be completely wrapped in a paper, we need to find its TSA
TSA = 2[(6)(4) + (4)(1) + (6)(1)] = 2[24 + 4 + 6] = 2[34] = 68\(in^2\)
Remember - The sheet cannot be torn, so it can only be folded. Which means, the area of the sheet has to be greater than the TSA
A. 12in x 4in = 48\(in^2\)
B. 12in x 6in = 72\(in^2\)
C. 13in x 4in = 52\(in^2\)
D. 14in x 5in = 70\(in^2\)
E. 15in x 4in = 60\(in^2\)
F. 15in x 5in = 75\(in^2\)
Hence, option B, D and F
gmatclubot
Re: A rectangular box with length 6in, width 4in and height 1in has to be [#permalink]
24 Mar 2022, 22:12
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