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If a > x > y , which of the following must be true ? a > 0 x > y a2x
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20 Mar 2023, 05:17
20 Mar 2023, 05:17
Expert Reply
00:00
Question Stats:
73% (01:07) correct
26% (01:34) wrong based on 15 sessions
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If \(a > x > y\) , which of the following must be true ?
Indicate all that apply
\(a > 0\)
\(x > –y\)
\(a^2x ≥ a^2y\)
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE INEQUALITIES
Indicate all that apply
\(a > 0\)
\(x > –y\)
\(a^2x ≥ a^2y\)
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE INEQUALITIES
Re: If a > x > y , which of the following must be true ? a > 0 x > y a2x
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11 Apr 2023, 10:55
11 Apr 2023, 10:55
Expert Reply
1) a could be also negative
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
Re: If a > x > y , which of the following must be true ? a > 0 x > y a2x
[#permalink]
07 Oct 2023, 06:22
07 Oct 2023, 06:22
Carcass wrote:
1) a could be also negative
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
For 3) after dividing by a^2, we get x >= y. This implies that x could be = y which is in violation of the given constraint. Therefore, none of the given options is correct.
