GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
How many liters of pure alcohol must be added to a 90-liter solution t
[#permalink]
16 Nov 2023, 02:23
16 Nov 2023, 02:23
Expert Reply
00:00
Question Stats:
60% (01:43) correct
40% (02:23) wrong based on 15 sessions
Hide Show timer Statistics
How many liters of pure alcohol must be added to a 90-liter solution that is 20 percent alcohol in order to produce a solution that is at least 25 percent alcohol?
Indicate all possible values.
(A) 4.5
(B) 5.0
(C) 5.5
(D) 6.0
(E) 6.5
Indicate all possible values.
(A) 4.5
(B) 5.0
(C) 5.5
(D) 6.0
(E) 6.5
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Manager
Joined: 11 Nov 2023
Posts: 228
Given Kudos: 78
WE:Business Development (Advertising and PR)
Re: How many liters of pure alcohol must be added to a 90-liter solution t
[#permalink]
01 Dec 2023, 13:09
01 Dec 2023, 13:09
1
The volume of alcohol in a solution = volume of solution * concentration of solution.
The current volume of alcohol = 90 * 0.20 = 18 liters.
Let x be the amount of pure alcohol to be added. We know that the final concentration is at least 0.25%. We can set up the equation as
\(\frac{(18+x)}{(90+x)} ≥ 0.25\)
Solving for this equation, we get \(x ≥ 6\). Since both 6.0 and 6.5 are equal to or greater than 6, the answers are D and E.
The current volume of alcohol = 90 * 0.20 = 18 liters.
Let x be the amount of pure alcohol to be added. We know that the final concentration is at least 0.25%. We can set up the equation as
\(\frac{(18+x)}{(90+x)} ≥ 0.25\)
Solving for this equation, we get \(x ≥ 6\). Since both 6.0 and 6.5 are equal to or greater than 6, the answers are D and E.
gmatclubot
Re: How many liters of pure alcohol must be added to a 90-liter solution t [#permalink]
01 Dec 2023, 13:09
Moderators:
