OFFICIAL EXPLANATION


The number $\(887980 x y\)$ is divisible by 3 , only when the sum of its digits, i.e., $\(8+8+7+9+8+0+x+y=40+x+y\)$ is divisible by 3 .

Therefore, $\(x+y\)$ could be $\(2,5,8,11,14\)$, or 17 .
Since the given number is also divisible by 8 , the number formed by the last three digits, i.e., $x y$ should be divisible by 8 .

Therefore, $\(x y\)$ could be $\(08,16,24,32,40,48,56,64,72,80,88\)$ or 96 .

Combining both the conditions, the possible values of $\(x y\)$ could be 08,32 , and 56 .

Hence, the values of $\(x+y\)$ could be 8,5 , and 11 .

Thus, the correct answer choices are $B, D$ and $G$.