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If x,y, and z are three non-zero numbers
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26 Apr 2021, 10:20
26 Apr 2021, 10:20
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If x,y, and z are three non-zero numbers and xy>0 and yz<0, which of the following must be negative?
A. xyz
B. xyz^2
C. xy^2z
D. xy^2z^2
E. x^2y^2z^2
F. x^2yz
G. -(x^2y^2z^2)
H. x^2yz^2
I. x(-y)z^2
J. -(xyz^2)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. xyz
B. xyz^2
C. xy^2z
D. xy^2z^2
E. x^2y^2z^2
F. x^2yz
G. -(x^2y^2z^2)
H. x^2yz^2
I. x(-y)z^2
J. -(xyz^2)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Official Answer
C,F,G,I,J
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Re: If x,y, and z are three non-zero numbers
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27 Apr 2021, 07:38
27 Apr 2021, 07:38
1
Carcass wrote:
If x,y, and z are three non-zero numbers and xy>0 and yz<0, which of the following must be negative?
A. xyz
B. xyz^2
C. xy^2z
D. xy^2z^2
E. x^2y^2z^2
F. x^2yz
G. -(x^2y^2z^2)
H. x^2yz^2
I. x(-y)z^2
J. -(xyz^2)
A. xyz
B. xyz^2
C. xy^2z
D. xy^2z^2
E. x^2y^2z^2
F. x^2yz
G. -(x^2y^2z^2)
H. x^2yz^2
I. x(-y)z^2
J. -(xyz^2)
Given: xy > 0 and yz < 0
We can have two cases;
Case I: when x is +ve, y is +ve and z is -ve
Case II: when x is -ve, y is -ve and z is +ve
A. xyz < 0
Case I: Yes
Case II: No
B. xyz^2 < 0
Case I: No
Case II: No
C. xy^2z < 0
Case I: Yes
Case II: Yes
D. xy^2z^2 < 0
Case I: No
Case II: Yes
E. x^2y^2z^2 < 0
Case I: No
Case II: No
F. x^2yz < 0
Case I: Yes
Case II: Yes
G. -(x^2y^2z^2) < 0
Case I: Yes
Case II: Yes
H. x^2yz^2 < 0
Case I: No
Case II: Yes
I. x(-y)z^2 < 0
Case I: Yes
Case II: Yes
J. -(xyz^2) < 0[/quote]
Case I: Yes
Case II: Yes
Hence, option C, F, G, I, and J
gmatclubot
Re: If x,y, and z are three non-zero numbers [#permalink]
27 Apr 2021, 07:38
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