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A class consists of 12 girls and 20 boys. One quarter of the
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30 Jul 2018, 10:54
30 Jul 2018, 10:54
Expert Reply
00:00
Question Stats:
71% (00:50) correct
28% (01:15) wrong based on 88 sessions
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A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?
(A) \(\frac{3}{32}\)
(B) \(\frac{9}{32}\)
(C) \(\frac{3}{8}\)
(D) \(\frac{23}{32}\)
(E) \(\frac{29}{32}\)
(A) \(\frac{3}{32}\)
(B) \(\frac{9}{32}\)
(C) \(\frac{3}{8}\)
(D) \(\frac{23}{32}\)
(E) \(\frac{29}{32}\)
Re: A class consists of 12 girls and 20 boys. One quarter of the
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31 Jul 2018, 03:01
31 Jul 2018, 03:01
sandy wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?
(A) \(\frac{3}{32}\)
(B) \(\frac{9}{32}\)
(C) \(\frac{3}{8}\)
(D) \(\frac{23}{32}\)
(E) \(\frac{29}{32}\)
(A) \(\frac{3}{32}\)
(B) \(\frac{9}{32}\)
(C) \(\frac{3}{8}\)
(D) \(\frac{23}{32}\)
(E) \(\frac{29}{32}\)
Total : 12 + 20 = 32
Girls who have blue eyes = 12*1/4 = 3
Girls who don't have blue eyes = 9
Probability = 9/32
The best answer is B.
Re: A class consists of 12 girls and 20 boys. One quarter of the
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08 Aug 2018, 18:12
08 Aug 2018, 18:12
Expert Reply
Explanation
The probability of any outcome is equal to the number of desired outcomes divided by the total number of outcomes. There are 12 girls and 20 boys in the classroom. If one-quarter of the girls have blue eyes, then there are \((12)\frac{1}{3} = 3\) girls with blue eyes.
Therefore, there are \(12 - 3 = 9\) girls who do not have blue eyes. The total number of ways in which a child could be chosen is the total number of children in the class, namely 12 + 20 = 32. Therefore, the probability of choosing a girl who does not have blue eyes equals the number of girls without blue eyes divided by the total number of children, which is \(\frac{9}{32}\).
The probability of any outcome is equal to the number of desired outcomes divided by the total number of outcomes. There are 12 girls and 20 boys in the classroom. If one-quarter of the girls have blue eyes, then there are \((12)\frac{1}{3} = 3\) girls with blue eyes.
Therefore, there are \(12 - 3 = 9\) girls who do not have blue eyes. The total number of ways in which a child could be chosen is the total number of children in the class, namely 12 + 20 = 32. Therefore, the probability of choosing a girl who does not have blue eyes equals the number of girls without blue eyes divided by the total number of children, which is \(\frac{9}{32}\).
