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If |y|≤ - 4x and |3x - 4|= 2x + 6
[#permalink]
22 Aug 2018, 06:42
22 Aug 2018, 06:42
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Question Stats:
69% (02:24) correct
30% (02:16) wrong based on 13 sessions
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The question in 5lb. Manhattan,
If \(|y| ≤ –4x\) and \(|3x – 4| = 2x + 6\), what is the value of x?
(A) \(-3\)
(B) \(-\frac{1}{3}\)
(C) \(-\frac{2}{5}\)
(D) \(\frac{1}{3}\)
(E) \(10\)
How to solve such a question? I get a lot of confused while solving inequality question. It would be appreciable if someone could share tips or tricks, or any kind of pdf.
If \(|y| ≤ –4x\) and \(|3x – 4| = 2x + 6\), what is the value of x?
(A) \(-3\)
(B) \(-\frac{1}{3}\)
(C) \(-\frac{2}{5}\)
(D) \(\frac{1}{3}\)
(E) \(10\)
How to solve such a question? I get a lot of confused while solving inequality question. It would be appreciable if someone could share tips or tricks, or any kind of pdf.
Re: Two unkowns in inequalities
[#permalink]
22 Aug 2018, 07:48
22 Aug 2018, 07:48
1
Expert Reply
Hi,
please before to post a question look at the rules of the board for posting https://gre.myprepclub.com/forum/rules-for ... -1083.html
Post it under the right sub-forum NOT in general quant section that is reserved for strategies and else.
Also, read how to format a question in a proper manner https://gre.myprepclub.com/forum/qq-how-to ... -2357.html
Back to the question:
Since |y|≤ - 4x, we have x≤ 0 (Absolute value is non-negative)
Given, |3x - 4|= 2x + 6 when 3x-4>0 or x>\(\frac{4}{3}\) (Not possible since x is not positive)
Again |3x - 4|=-(3x-4)=2x + 6
Or, 4-3x=2x+6
Or, 5x=-2
Or, \(x=\frac{-2}{5}\)
Hope this helps
please before to post a question look at the rules of the board for posting https://gre.myprepclub.com/forum/rules-for ... -1083.html
Post it under the right sub-forum NOT in general quant section that is reserved for strategies and else.
Also, read how to format a question in a proper manner https://gre.myprepclub.com/forum/qq-how-to ... -2357.html
Back to the question:
Since |y|≤ - 4x, we have x≤ 0 (Absolute value is non-negative)
Given, |3x - 4|= 2x + 6 when 3x-4>0 or x>\(\frac{4}{3}\) (Not possible since x is not positive)
Again |3x - 4|=-(3x-4)=2x + 6
Or, 4-3x=2x+6
Or, 5x=-2
Or, \(x=\frac{-2}{5}\)
Hope this helps
gmatclubot
Re: Two unkowns in inequalities [#permalink]
22 Aug 2018, 07:48
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