Hi,
please
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https://gre.myprepclub.com/forum/qq-how-to ... -2357.htmlBack to the question:
Since |y|≤ - 4x, we have x≤ 0 (Absolute value is non-negative)
Given, |3x - 4|= 2x + 6 when 3x-4>0 or x>\(\frac{4}{3}\) (Not possible since x is not positive)
Again |3x - 4|=-(3x-4)=2x + 6
Or, 4-3x=2x+6
Or, 5x=-2
Or, \(x=\frac{-2}{5}\)
Hope this helps