GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure shown, ABCDEF is a regular hexagon and AOF is
[#permalink]
21 Mar 2019, 12:01
21 Mar 2019, 12:01
Expert Reply
00:00
Question Stats:
94% (00:36) correct
5% (00:59) wrong based on 17 sessions
Hide Show timer Statistics
Attachment:
#GREpracticequestion In the figure shown, ABCDEF is.jpg [ 18.83 KiB | Viewed 4487 times ]
In the figure shown, ABCDEF is a regular hexagon and AOF is an equilateral triangle. The perimeter of \(∆AOF\) is 2a feet. What is the perimeter of the hexagon in feet?
(A) 2a
(B) 3a
(C) 4a
(D) 6a
(E) 12a
Target Test Prep Representative
Joined: 12 Sep 2018
Status:Founder & CEO, Target Test Prep
Affiliations: Target Test Prep
Posts: 2083
Given Kudos: 5
Re: In the figure shown, ABCDEF is a regular hexagon and AOF is
[#permalink]
04 Apr 2019, 17:29
04 Apr 2019, 17:29
1
Expert Reply
Carcass wrote:
Attachment:
#GREpracticequestion In the figure shown, ABCDEF is.jpg
In the figure shown, ABCDEF is a regular hexagon and AOF is an equilateral triangle. The perimeter of \(∆AOF\) is 2a feet. What is the perimeter of the hexagon in feet?
(A) 2a
(B) 3a
(C) 4a
(D) 6a
(E) 12a
We see that each side of the triangle = each side of the hexagon = 2a/3, so the perimeter of the hexagon is 2a/3 x 6 = 4a.
Answer: C
gmatclubot
Re: In the figure shown, ABCDEF is a regular hexagon and AOF is [#permalink]
04 Apr 2019, 17:29
Moderators:
