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Re: If 3c + 2d = 8 and c < –1, which one of the following could [#permalink]
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Madhavi1990 wrote:
jwolbrum wrote:
We should start by getting our equation in terms of d.

3c + 2d = 8
2d = 8 - 3c
d = 4 - 1.5(c)

We can now consider what happens at the boundary condition for c. Let's plug in c = -1 and see what happens.

d = 4 - 1.5(-1)
d = 5.5

However, c must be smaller than -1. Since we're subtracting a negative number, we know that the smaller c gets, the larger d will get. This means that d must be at least a little bigger than 5.5. Only E satisfies that requirement.






How can we substitute C with -1? Its stated C < -1 so c ideally should be anything above C = -1.0001 at least. Can this be explained?



It doesn't matter. Since it should be lesser than -1 you can take that as base value and calculate based on that.
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If 3c + 2d = 8 and c < 1, which one of the following could [#permalink]
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Now since \(c<-1\) means \(c\) could be anything from \(1.000000001\) to \(-10000000\), lets assume \(c=-1\) and see what value \(d\) takes.

\(3c+2d = 8\)

\(3(-1) + 2d =8\)

\(-3+2d=8\)

\(2d=8+3\)

\(2d=11\)

\(d=5.5\)

Now \(c=-1\) gave us \(d=5.5\)

If \(c<-1\), then the value of \(d\) would be greater than \(5.5\).

\(6.5\) is the answer Choice E and that is the correct answer.
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