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A regular, six-sided die is rolled three times. What is the
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26 Sep 2019, 08:52
26 Sep 2019, 08:52
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A regular, six-sided die is rolled three times. What is the probability that each of the three rolls will be an odd number?
A. \(\frac{1}{2}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{6}\)
D. \(\frac{1}{8}\)
E. \(\frac{1}{216}\)
Kudos for the right answer and explanation
A. \(\frac{1}{2}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{6}\)
D. \(\frac{1}{8}\)
E. \(\frac{1}{216}\)
Kudos for the right answer and explanation
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Joined: 10 Apr 2015
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Re: A regular, six-sided die is rolled three times. What is the
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26 Sep 2019, 09:10
26 Sep 2019, 09:10
1
Carcass wrote:
A regular, six-sided die is rolled three times. What is the probability that each of the three rolls will be an odd number?
A. \(\frac{1}{2}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{6}\)
D. \(\frac{1}{8}\)
E. \(\frac{1}{216}\)
A. \(\frac{1}{2}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{6}\)
D. \(\frac{1}{8}\)
E. \(\frac{1}{216}\)
P(all 3 rolls are odd) = P(1st roll is odd AND 2nd roll is odd AND 3rd roll is odd)
= P(1st roll is odd) x P(2nd roll is odd) x P(3rd roll is odd)
= \(\frac{1}{2}\) x \(\frac{1}{2}\) x \(\frac{1}{2}\)
= \(\frac{1}{8}\)
Answer: D
Cheers,
Brent
Re: A regular, six-sided die is rolled three times. What is the
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29 Sep 2019, 23:27
29 Sep 2019, 23:27
1
Key here is recalling when to multiply the probability of each event and when to add them: With events that are "AND", we must multiply; with events that are "OR", we must add.
·
On a die, there are 3 odd numbers and 3 even numbers.
The first roll's chances for an odd is 3/6, the second is also 3/6, and third is 3/6. Since 3/6 simplifies to 1/2, we use 1/2 · 1/2 · 1/2 = 1/8. 1/8 is Choice D.
·
On a die, there are 3 odd numbers and 3 even numbers.
The first roll's chances for an odd is 3/6, the second is also 3/6, and third is 3/6. Since 3/6 simplifies to 1/2, we use 1/2 · 1/2 · 1/2 = 1/8. 1/8 is Choice D.
