Last visit was: 27 Apr 2024, 14:25 It is currently 27 Apr 2024, 14:25

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 28660
Own Kudos [?]: 33141 [0]
Given Kudos: 25178
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 28660
Own Kudos [?]: 33141 [0]
Given Kudos: 25178
Send PM
avatar
Intern
Intern
Joined: 10 Aug 2019
Posts: 19
Own Kudos [?]: 10 [0]
Given Kudos: 0
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11692 [1]
Given Kudos: 136
Send PM
Re: If the operation @ is defined by x@y=(xy)^1/2 for all [#permalink]
1
Carcass wrote:
If the operation @ is defined by \(x@y=\sqrt{xy}\) for all positive numbers x and y, then (5@45)@60 =

(A) 30
(B) 60
(C) 90
(D) \(30\sqrt{15}\)
(E) \(60\sqrt{15}\)


We want to evaluate: (5 @ 45) @ 60

Start with (5 @ 45)
(5 @ 45) = √[(5)(45)]
= √225
= 15


So, (5 @ 45) @ 60 = 15 @ 60
From here, 15 @ 60 = √[(15)(60)]
= √900
= 30

Answer: A
avatar
Intern
Intern
Joined: 25 Jul 2020
Posts: 33
Own Kudos [?]: 25 [1]
Given Kudos: 0
GRE 1: Q170 V157
Send PM
Re: If the operation @ is defined by x@y=(xy)^1/2 for all [#permalink]
1
(5@45)@60

\(\sqrt{\sqrt{5 \times 45} \times 60}\)
\(\sqrt{\sqrt{225} \times 60}\)
\(\sqrt{900}\)
= 30
Moderator
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1085
Own Kudos [?]: 884 [1]
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Send PM
If the operation @ is defined by x@y=(xy)^1/2 for all [#permalink]
1
Given that \(x@y=\sqrt{xy}\) and we need to find the value of (5@45)@60

Let's start by finding the value of 5@45

To find 5@45 we need to compare 5@45 with x@y and see what is before the @ and what is after
=> x = 5 and y = 45

=> to find the value of 5@45 we need to replace x with 5 and y with 45 in \(x@y=\sqrt{xy}\)
=> \(5@45=\sqrt{5*45}\) = \(\sqrt{5*5*9}\) = \(\sqrt{5^2*3^2}\) = 5*3 = 15

=> (5@45)@60 = 15@60

Similarly, \(15@60=\sqrt{15*60}\) = \(\sqrt{15*15*4}\) = \(\sqrt{15^2*2^2}\) = 15*2 = 30

So, Answer will be A
Hope it helps!

Watch the following video to learn the Basics of Functions and Custom Characters

Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne