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Re: The average (arithmetic mean) of 13 numbers is 70. If the av [#permalink]
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average of 13 numbers = 70
=> sum of 13 numbers = 70*13 = 910

average of 10 numbers = 90
=> sum of 10 numbers = 09*10 = 900

So, sum of remaining 3 numbers = 910 - 900 = 10
=> Average of remaining 3 numbers = 10/3 (B)
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Re: The average (arithmetic mean) of 13 numbers is 70. If the av [#permalink]
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average of 13 numbers*13 = 70*10=910=x(sum of 13 nums )
average of 10 numbers*10 = 90*10=900=y(sum of 10 nums)
required avg=(x-y)/3 =10/3(B)
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Re: The average (arithmetic mean) of 13 numbers is 70. If the av [#permalink]
1
Theory

    ➡ Average = Sum of all the Values / Total Number of Values
    ➡ Sum of All the values = Average * Total Number of Values

The average (arithmetic mean) of 13 numbers is 70

Sum of 13 numbers = Average * 13 = 70 * 13 = 910

The average of 10 of these numbers is 90

Sum of 10 numbers = Average * 10 = 90 * 10 = 900

The average of the other 3 numbers

Average = Sum of 3 numbers / 3 = Sum of 13 numbers - Sum of 10 numbers/4 = \(\frac{910 - 900 }{ 3}\)
= \(\frac{10}{3}\)

So, Answer will be B.
Hope it helps!

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