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In a set of 24 cards, each card is numbered with a different
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27 Aug 2020, 09:52
27 Aug 2020, 09:52
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In a set of 24 cards, each card is numbered with a different positive integer from 1 to 24. One card will be drawn at random from the set. What is the probability that the card drawn will have either a number that is divisible by both 2 and 3 or a number that is divisible by 7 ?
A. 3/24
B. 4/24
C. 7/24
D. 8/24
E. 17/24
A. 3/24
B. 4/24
C. 7/24
D. 8/24
E. 17/24
Re: In a set of 24 cards, each card is numbered with a different
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27 Aug 2020, 09:53
27 Aug 2020, 09:53
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
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Re: In a set of 24 cards, each card is numbered with a different
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27 Aug 2020, 10:22
27 Aug 2020, 10:22
Carcass wrote:
In a set of 24 cards, each card is numbered with a different positive integer from 1 to 24. One card will be drawn at random from the set. What is the probability that the card drawn will have either a number that is divisible by both 2 and 3 or a number that is divisible by 7 ?
A. 3/24
B. 4/24
C. 7/24
D. 8/24
E. 17/24
A. 3/24
B. 4/24
C. 7/24
D. 8/24
E. 17/24
P(event) = (number of outcomes that meet the given condition)/(total number of possible outcomes)
So, P(selected number is divisible by both 2 and 3 OR is divisible by 7) = number of integers that are divisible by both 2 and 3 OR are divisible by 7/24
number of integers that are divisible by both 2 and 3 OR are divisible by 7
The integers that meet this condition are: 6, 7, 12, 14, 18, 21, 24
There are 7 such numbers
So, P(selected number is divisible by both 2 and 3 OR is divisible by 7) = 7/24
Answer: C
Cheers,
Brent
