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Re: What is the total number of ways in which Dishu can distribu [#permalink]
Mugdho wrote:
KarunMendiratta wrote:
Mugdho wrote:
What is the total number of ways in which Dishu can distribute 9 distinct gifts among his 8 distinct girlfriends such that each of them gets at least one gift?

a)72*8!
b)144×8!
c)36*72*8!
d)12*7!*8
e)72*7!

Posted from my mobile device



One among 8 gfs will get 2 gifts and remaining 7 will get one. So total of 9 gifts will be distributed among 8 gfs. i.e; 11111112
Gf who will get 2 gifts can be find out in 8C1 ways = 8 ways.
Now 2 gifts can be given to selected gf in 9C2 ways. And remaining 7 gifts can be given to remaining 7 gf in 7! ways.
So total no of ways= 8 × 9C2 × 7!
= 8×(9×8)2×7!

= 36 × 8 × 7!
= 36 × 8!


You are left with just one gift! How can you give 2 gifts out of 9 when you have already selected a girl who will receive 2 gifts!
It should be \(^9C_1\)
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