If the two-digit integers A and B are positive and have the same digit
[#permalink]
23 Aug 2021, 06:53
Given: A and B are two positive two-digit integers with their digits reversed.
Let A be of the form (10x + y), where x and y are its tens and units digits respectively.
This implies that B is of the form (10y + x), where y and x are its tens and units digits respectively.
Taking the difference between A and B:
(10x + y) - (10y + x) = 9(x - y)
Hence, the difference between A and B has to be a multiple of 9. Looking at the options, 21 is the only choice which is not a multiple of 9.
Answer B