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In equilateral triangle ABC, above, AB = 12, and M is the midpoint of
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14 Oct 2021, 09:25
14 Oct 2021, 09:25
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77% (01:28) correct
22% (00:53) wrong based on 18 sessions
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In equilateral triangle ABC, above, AB = 12, and M is the midpoint of AC. Point C is the center of the circle. What is the shaded area?
\(6\pi\)
\(7.2\pi\)
\(10\pi\)
\(24\pi\)
\(30\pi\)
In equilateral triangle ABC, above, AB = 12, and M is the midpoint of
[#permalink]
14 Oct 2021, 10:40
14 Oct 2021, 10:40
Carcass wrote:
Attachment:
screenshot.145.jpg
In equilateral triangle ABC, above, AB = 12, and M is the midpoint of AC. Point C is the center of the circle. What is the shaded area?
\(6\pi\)
\(7.2\pi\)
\(10\pi\)
\(24\pi\)
\(30\pi\)
Since it's a equilateral triangle the angle ACB is 60 degree and radius is 6.
The shaded region is 5/6 of the total area = \(\frac{5}{6 }* \pi * 6^2 = 30\pi\)
Answer is E)
gmatclubot
In equilateral triangle ABC, above, AB = 12, and M is the midpoint of [#permalink]
14 Oct 2021, 10:40
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