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A box contains 4 red chips and 2 blue chips. If two chips ar
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04 Feb 2020, 10:31
04 Feb 2020, 10:31
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Question Stats:
89% (01:26) correct
10% (01:34) wrong based on 39 sessions
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A box contains 4 red chips and 2 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?
[A] \(\frac{ 1}{2}\)
[b] \(\frac{ 8}{15}\)
[C] \(\frac{ 7}{12}\)
[D] \(\frac{ 2}{3}\)
[E] \(\frac{ 7}{10}\)
[A] \(\frac{ 1}{2}\)
[b] \(\frac{ 8}{15}\)
[C] \(\frac{ 7}{12}\)
[D] \(\frac{ 2}{3}\)
[E] \(\frac{ 7}{10}\)
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Joined: 10 Apr 2015
Posts: 6218
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Re: A box contains 4 red chips and 2 blue chips. If two chips ar
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05 Feb 2020, 06:48
05 Feb 2020, 06:48
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huda wrote:
A box contains 4 red chips and 2 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?
[A] \(\frac{ 1}{2}\)
\(\frac{ 8}{15}\)
[C] \(\frac{ 7}{12}\)
[D] \(\frac{ 2}{3}\)
[E] \(\frac{ 7}{10}\)
[A] \(\frac{ 1}{2}\)
\(\frac{ 8}{15}\)
[C] \(\frac{ 7}{12}\)
[D] \(\frac{ 2}{3}\)
[E] \(\frac{ 7}{10}\)
P(different colors) = P(1st chip is red [b]and 2nd chip is blue OR 1st chip is blue and 2nd chip is red)
= P(1st chip is red and 2nd chip is blue) + P(1st chip is blue and 2nd chip is red)
= P(1st chip is red) x P(2nd chip is blue) + P(1st chip is blue) x P(2nd chip is red)
= 4/6 x 2/5 + 2/6 x 4/5
= 8/30 + 8/30
= 16/30
= 8/15
Answer: B
Cheers,
Brent
Re: A box contains 4 red chips and 2 blue chips. If two chips ar
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24 Feb 2023, 10:53
24 Feb 2023, 10:53
Hello from the GRE Prep Club BumpBot!
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
