huda wrote:
A box contains 4 red chips and 2 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?
[A] \(\frac{ 1}{2}\)
\(\frac{ 8}{15}\)
[C] \(\frac{ 7}{12}\)
[D] \(\frac{ 2}{3}\)
[E] \(\frac{ 7}{10}\)
P(different colors) = P(1st chip is red [b]
and 2nd chip is blue
OR 1st chip is blue
and 2nd chip is red)
= P(1st chip is red
and 2nd chip is blue)
+ P(1st chip is blue
and 2nd chip is red)
= P(1st chip is red)
x P(2nd chip is blue)
+ P(1st chip is blue)
x P(2nd chip is red)
= 4/6
x 2/5
+ 2/6
x 4/5
= 8/30
+ 8/30
= 16/30
= 8/15
Answer: B
Cheers,
Brent