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A certain team consists of 4 professors and 6 teaching assistants. How
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21 Oct 2021, 09:32
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A certain team consists of 4 professors and 6 teaching assistants. How many different teams of 3 can be formed in which at least one member of the group is a professor? (Two groups are considered different if at least one group member is different.)
Re: A certain team consists of 4 professors and 6 teaching assistants. How
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21 Oct 2021, 09:41
Carcass wrote:
A certain team consists of 4 professors and 6 teaching assistants. How many different teams of 3 can be formed in which at least one member of the group is a professor? (Two groups are considered different if at least one group member is different.)
A. 48 B. 100 C. 120 D. 288 E. 600
When we see a counting question involving "at least", we should consider using the nice rule: Total number of outcomes that FOLLOW a rule = (TOTAL number of outcomes that IGNORE the rule) - (number of outcomes that BREAK the rule)
Here, we have: Total number of teams with AT LEAST one professor = (TOTAL number of teams with ANY NUMBER of professors) - (number of teams with ZERO professors)
TOTAL number of teams with ANY NUMBER of professors W'ere ignoring the rule that talks about the number of professors on a team. There are 10 people in total, and we must select 3 to be on a team. Since the order in which we select the people does not matter, we can use COMBINATIONS We can select 3 people from 10 people in 10C3 ways (= 120 teams)
Number of teams with ZERO professors This means all 3 team members must be assistants There are 6 assistants in total, and we must select 3 of them to be on a team. Since the order in which we select the assistants does not matter, we can use COMBINATIONS We can select 3 assistants from 6 assistants in 6C3 ways (= 20 teams)
ASIDE: The video hello explain how to calculate combinations (like 6C3) in your head
Total number of teams with AT LEAST one professor = (TOTAL number of teams with ANY NUMBER of professors) - (number of teams with ZERO professors) = 120 - 20 = 100
Answer: B
Cheers, Brent
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