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If x ≠ –2, then 8x^2 − 32/4x + 8 =?
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17 Nov 2021, 03:06
17 Nov 2021, 03:06
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Question Stats:
62% (01:00) correct
37% (00:44) wrong based on 16 sessions
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If \(x ≠ –2\), then \(\frac{8x^2 − 32}{4x + 8}\) =
(A) \(2(x – 2)\)
(B) \(2(x – 4)\)
(C) \(8(x + 2)\)
(D) \(x – 2\)
(E) \(x + 4\)
GRE Tips and Tricks - UPDATED 11/15/2021
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
(A) \(2(x – 2)\)
(B) \(2(x – 4)\)
(C) \(8(x + 2)\)
(D) \(x – 2\)
(E) \(x + 4\)
GRE Tips and Tricks - UPDATED 11/15/2021
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
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Re: If x ≠ –2, then 8x^2 − 32/4x + 8 =?
[#permalink]
17 Nov 2021, 06:25
17 Nov 2021, 06:25
1
Carcass wrote:
If \(x ≠ –2\), then \(\frac{8x^2 − 32}{4x + 8}\) =
(A) \(2(x – 2)\)
(B) \(2(x – 4)\)
(C) \(8(x + 2)\)
(D) \(x – 2\)
(E) \(x + 4\)
(A) \(2(x – 2)\)
(B) \(2(x – 4)\)
(C) \(8(x + 2)\)
(D) \(x – 2\)
(E) \(x + 4\)
\(\frac{8x^2 − 32}{4x + 8}=\frac{8(x^2 − 4)}{4(x + 2)}\) [factored out the greatest common factor from numerator and denominator]
\(=\frac{2(x^2 − 4)}{(x + 2)}\) [simplified fraction]
\(=\frac{2(x - 2)(x + 2)}{(x + 2)}\) [factored that the difference of squares in the numerator]
\(=2(x - 2)\) [simplified fraction]
Answer: A
gmatclubot
Re: If x ≠ –2, then 8x^2 − 32/4x + 8 =? [#permalink]
17 Nov 2021, 06:25
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