GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If x = 2 and y = –3, then y^2 − (x − [y + 1/2])− 2*3 =
[#permalink]
26 Nov 2021, 06:15
26 Nov 2021, 06:15
Expert Reply
00:00
Question Stats:
88% (01:28) correct
11% (01:59) wrong based on 9 sessions
Hide Show timer Statistics
If \(x = 2\) and \(y = –3\), then \(y^2 − (x − [y + \frac{1}{2}])− 2*3 =\)
(A) \(− \frac{39}{2}\)
(B) \(− \frac{3}{2}\)
(C) \(0\)
(D) \(31\)
(E) \(43\)
(A) \(− \frac{39}{2}\)
(B) \(− \frac{3}{2}\)
(C) \(0\)
(D) \(31\)
(E) \(43\)
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If x = 2 and y = –3, then y^2 − (x − [y + 1/2])− 2*3 =
[#permalink]
26 Nov 2021, 06:21
26 Nov 2021, 06:21
Carcass wrote:
If \(x = 2\) and \(y = –3\), then \(y^2 − (x − [y + \frac{1}{2}])− 2*3 =\)
(A) \(− \frac{39}{2}\)
(B) \(− \frac{3}{2}\)
(C) \(0\)
(D) \(31\)
(E) \(43\)
(A) \(− \frac{39}{2}\)
(B) \(− \frac{3}{2}\)
(C) \(0\)
(D) \(31\)
(E) \(43\)
Plug \(x = 2\) and \(y = –3\) into the expression and evaluate as follows....
\(y^2 − (x − [y + \frac{1}{2}])− 2*3 =(-3)^2 − (2 − [(-3) + \frac{1}{2}])− 2*3 \)
\(=(-3)^2 − (2 − [(\frac{-6}{2}) + \frac{1}{2}])− 2*3 \)
\(=(-3)^2 − (2 − [\frac{-5}{2}])− 2*3 \)
\(=(-3)^2 − (\frac{4}{2} − [\frac{-5}{2}])− 2*3 \)
\(=(-3)^2 − (\frac{9}{2})− 2*3 \)
\(=9 − (\frac{9}{2})− 2*3 \)
\(=9 − (\frac{9}{2})−6 \)
\(=\frac{18}{2} − (\frac{9}{2})−\frac{12}{2} \)
\(=\frac{9}{2} −\frac{12}{2} \)
\(=−\frac{3}{2} \)
Answer: B
gmatclubot
Re: If x = 2 and y = –3, then y^2 − (x − [y + 1/2])− 2*3 = [#permalink]
26 Nov 2021, 06:21
Moderators:
