GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
How many 6 digit numbers can be formed using the digits
[#permalink]
Updated on: 20 Oct 2018, 10:23
Updated on: 20 Oct 2018, 10:23
1
Bookmarks
00:00
Question Stats:
100% (00:50) correct
0% (00:00) wrong based on 2 sessions
Hide Show timer Statistics
How many 6 digit numbers can be formed using the digits 1, 2, 3, 4 and 5 (repetitions allowed) such that the number reads the same from left to right or from right to left (e.g. 134431)?
(1) 6
(2) 12
(3) 24
(4) 36
Can anyone help me with it's solution?
(1) 6
(2) 12
(3) 24
(4) 36
Can anyone help me with it's solution?
Re: How many 6 digit numbers can be formed using the digits
[#permalink]
20 Oct 2018, 10:25
20 Oct 2018, 10:25
Expert Reply
Please, follow the rules for posting a question. https://gre.myprepclub.com/forum/rules-for ... -1083.html
They must go under the right subforum and not in general quant section.
Moreover, the question is missing the E answer choice.
Regards
They must go under the right subforum and not in general quant section.
Moreover, the question is missing the E answer choice.
Regards
Re: How many 6 digit numbers can be formed using the digits
[#permalink]
20 Oct 2018, 10:37
20 Oct 2018, 10:37
1
Expert Reply
Shad1968 wrote:
How many 6 digit numbers can be formed using the digits 1, 2, 3, 4 and 5 (repetitions allowed) such that the number reads the same from left to right or from right to left (e.g. 134431)?
(1) 6
(2) 12
(3) 24
(4) 36
Can anyone help me with it's solution?
(1) 6
(2) 12
(3) 24
(4) 36
Can anyone help me with it's solution?
As mentioned by Carcass too, choice E is missing and that may be the correct answer..
Way to go about it...
6 places... The last three are dependent on first three.. .... xyzzyx
So first , second and third can be any of the 5. - 1,2,3,4,5
So 5*5*5 and of course the last three will be same as first three so 5*5*5*1*1*1=125
These are of course called palindromes
