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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
What is the value of integer n if ((16/(10^n)))^2 = 0.04^2
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28 Dec 2022, 09:59
28 Dec 2022, 09:59
Expert Reply
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Question Stats:
100% (00:52) correct
0% (00:00) wrong based on 4 sessions
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What is the value of integer n if \((\sqrt{\frac{16}{10^n}})^2=0.04^2\)
A) 0
B) 1
C) 2
D) 3
E) 4
A) 0
B) 1
C) 2
D) 3
E) 4
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: What is the value of integer n if ((16/(10^n)))^2 = 0.04^2
[#permalink]
30 Dec 2022, 02:39
30 Dec 2022, 02:39
Expert Reply
1. get rid of the square power on both sides
\(\frac{16}{10^n}=0.0016\)
2. put the unknown variable on the left side
\(10^n= \frac{16}{0.0016}\) and now \(0.0016 = 16*10^(-4)\) so we get
\(10^n=\frac{16}{16}*10^4\) switch signs to +4 power when placed from denominator to nominator
3. \(10^n=1*10^4\) or n=4
Answer: E
\(\frac{16}{10^n}=0.0016\)
2. put the unknown variable on the left side
\(10^n= \frac{16}{0.0016}\) and now \(0.0016 = 16*10^(-4)\) so we get
\(10^n=\frac{16}{16}*10^4\) switch signs to +4 power when placed from denominator to nominator
3. \(10^n=1*10^4\) or n=4
Answer: E
gmatclubot
Re: What is the value of integer n if ((16/(10^n)))^2 = 0.04^2 [#permalink]
30 Dec 2022, 02:39
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