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Re: The three sides of a triangle measure x - 2, x + 1, and x + [#permalink]
2
asmasattar00 wrote:
Sanpreet wrote:
a+b>c
where a,b and c are the sides of a triangle

Sum of two sides of the triangle will always be greater than the 3rd side.

So, in option E substitute x=3
Then the sides are
1, 4, 5

1+4=5
Sum of two sides of the triangle will always be greater than the 3rd side.
Which is not true for option E

So, E is the Answer.


but for option E , when sides are 1,4 and 5
5+4=9>1 , means this rule valid in one case of this triangle.
kindly explain where I'm lacking the main concept , thanks



This rule should be valid for all the three cases i.e.,
if a, b and c are three sides of a triangle then all three of these inequalities should be true

a + b > c
b + c > a
c + a > b
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Re: The three sides of a triangle measure x - 2, x + 1, and x + [#permalink]
E is the answer
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Re: The three sides of a triangle measure x - 2, x + 1, and x + [#permalink]
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Re: The three sides of a triangle measure x - 2, x + 1, and x + [#permalink]
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