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7/3,7/4, 7/5,.... The first term of the infinite sequence shown is 7/
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27 Jul 2025, 01:35
27 Jul 2025, 01:35
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\(\frac{7}{3},\frac{7}{4}, \frac{7}{5},.... \)
The first term of the infinite sequence shown is \(\frac{7}{3}\), and each term thereafter has a numerator of 7 and a denominator that is 1 greater than the denominator of the preceding term. Which of the following terms of the sequence is equal to the 6th term of the sequence minus the \(7^{th}\) term of the sequence?
A. \(40^{th}\)
B. \(42^{nd}\)
C. \(44^{th}\)
D. \(70^{th}\)
E. \(72^{nd}\)
The OA will be automatically revealed on Sunday 27th of July 2025 02:35:15 PM Pacific Time Zone
The first term of the infinite sequence shown is \(\frac{7}{3}\), and each term thereafter has a numerator of 7 and a denominator that is 1 greater than the denominator of the preceding term. Which of the following terms of the sequence is equal to the 6th term of the sequence minus the \(7^{th}\) term of the sequence?
A. \(40^{th}\)
B. \(42^{nd}\)
C. \(44^{th}\)
D. \(70^{th}\)
E. \(72^{nd}\)
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The OA will be automatically revealed on Sunday 27th of July 2025 02:35:15 PM Pacific Time Zone
gmatclubot
7/3,7/4, 7/5,.... The first term of the infinite sequence shown is 7/ [#permalink]
27 Jul 2025, 01:35
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