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Re: In the figure above, the circumference of the circle is 20π [#permalink]
3152gs wrote:
simon1994 wrote:
So the rectangle is going have the greatest Area if it is a square.

We know that the circle has a diameter of 20.

The square will have this diameter as its diagonal. In every sqaure the diagonal is a side * sqRoot of 2. So here it is 20/(sqRoot2).

If we multiply 20/(sqRoot2) we obtain 200.


Can you please elaborate why it has to be a square to have maximum area ?


Great question.
To prove that the maximum area occurs when the shape is a square, we'd need to use some calculus (which is beyond the scope of the GRE).
So, let's just say it's a general property.

Cheers,
Brent
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Re: In the figure above, the circumference of the circle is 20π [#permalink]
1
What are the possibilities for the inscribed rectangle?
The inscribed rectangle can be stretched and pulled to extremes: extremely
long and thin, extremely tall and narrow, and somewhere in between:
The “long and thin” and “tall and narrow” rectangles have a very small area,
and the “in between” rectangle has the largest possible area. In fact, the
largest possible rectangle inscribed inside a circle is a square
In this problem, the circumference is equal to 20π = 2πr. Thus r = 10. The
square then has a side length of 10\sqrt{2}and an area of (10\sqrt{2} )2 = 200.
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