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The length of each edge of a cube equals 6. What is the dis
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26 Aug 2017, 02:22
26 Aug 2017, 02:22
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The length of each edge of a cube equals 6. What is the distance between the center of the cube to one of its vertices?
A. \(3 \sqrt{2}\)
B. \(6 \sqrt{2}\)
C. \(3 \sqrt{3}\)
D. \(4 \sqrt{3}\)
E. \(6 \sqrt{3}\)
Re: The length of each edge of a cube equals 6. What is the dis
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15 Sep 2017, 00:43
15 Sep 2017, 00:43
2
There is a shortcut for this The diagonal of Cube can be founded by the formula: Sqrt(Asqr+Bsqr+Csqr).Here A=B=C=6.
So diagonal is SQRT(36+36+36)=6sqrt3
from centre, Divide by 2.ie 3sqrt3.
Feel free to ask any questions.
So diagonal is SQRT(36+36+36)=6sqrt3
from centre, Divide by 2.ie 3sqrt3.
Feel free to ask any questions.
Re: The length of each edge of a cube equals 6. What is the dis
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18 Sep 2017, 01:04
18 Sep 2017, 01:04
1
Pushkar96 wrote:
There is a shortcut for this The diagonal of Cube can be founded by the formula: Sqrt(Asqr+Bsqr+Csqr).Here A=B=C=6.
So diagonal is SQRT(36+36+36)=6sqrt3
from centre, Divide by 2.ie 3sqrt3.
Feel free to ask any questions.
So diagonal is SQRT(36+36+36)=6sqrt3
from centre, Divide by 2.ie 3sqrt3.
Feel free to ask any questions.
It is even faster to remember that the diagonal of a cube is \(l*sqrt(3)\). Three dimensions, \(sqrt(3)\); while the square, two dimensions \(sqrt(2)\)
