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Six beads, each a different color, are put into a bag. How
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19 Oct 2017, 01:19
19 Oct 2017, 01:19
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Question Stats:
73% (00:40) correct
26% (00:41) wrong based on 15 sessions
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Six beads, each a different color, are put into a bag. How many different three-color combinations are possible if 3 beads are drawn out of the bag simultaneously? (Assume the order of the colors does not matter.)
(A) 6
(B) 9
(C) 18
(D) 20
(E) 120
Kudos for correct solution.
(A) 6
(B) 9
(C) 18
(D) 20
(E) 120
Kudos for correct solution.
Re: Six beads, each a different color, are put into a bag. How
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19 Oct 2017, 01:30
19 Oct 2017, 01:30
1
Since the order does not matter we are talking about combinations. Then, the problem is solved by computing \(\frac{6!}{3!3!} = \frac{6*5*4}{2*3} = 20\).
Answer D
Answer D
gmatclubot
Re: Six beads, each a different color, are put into a bag. How [#permalink]
19 Oct 2017, 01:30
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