GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In Cytherea Corporation, each employee was given an interper
[#permalink]
04 Dec 2017, 03:05
04 Dec 2017, 03:05
1
1
Bookmarks
00:00
Question Stats:
100% (01:18) correct
0% (00:00) wrong based on 16 sessions
Hide Show timer Statistics
In Cytherea Corporation, each employee was given an interpersonal assessment with a score from 0 to 60. Te average score among all male employees was 35, and the average score for all employees was 39. If Cytherea Corporation has 40 male employees and 10 female employees, what was the average score among all female employees?
A. 40
B. 43
C. 47
D. 51
E. 55
Kudos for correct solution.
A. 40
B. 43
C. 47
D. 51
E. 55
Kudos for correct solution.
Re: In Cytherea Corporation, each employee was given an interper
[#permalink]
04 Dec 2017, 05:51
04 Dec 2017, 05:51
3
The standard, mathematical approach (should take not more than a minute, quicker if you're good with mental math):
Total score of the male employees = 35 * 40
Total score of the female employees = x * 10
\(Overall\,average = \frac{total\,score\,of\,males\,+\,total\,score\,of\,females}{total\,number\,of\,employees}\)
\(39 = \frac{35\,*\,40 + x\,*\,10}{50}\)
Divide the equation by 10,
\(39 * 5 = 35 * 4 + x\)
\(x = 39 * 5 - 35 * 4\)
\(x = 55\)
Alternatively, using a higher level of logic and reduced math: The mean of all males is 35. The mean of all employees is 39 (this does not mean the mean of all females is 43 because the number of females is not the same as that of males). This difference of 4 would equate to the same difference from the mean female score (let's say y). The weighted difference for males is 4 * 40. But we have 10 female employees, so 4 * 40 = 10 * x where x is the additional female score. It turns out to be 16, so the mean female score is 39 + 16 = 55.
Total score of the male employees = 35 * 40
Total score of the female employees = x * 10
\(Overall\,average = \frac{total\,score\,of\,males\,+\,total\,score\,of\,females}{total\,number\,of\,employees}\)
\(39 = \frac{35\,*\,40 + x\,*\,10}{50}\)
Divide the equation by 10,
\(39 * 5 = 35 * 4 + x\)
\(x = 39 * 5 - 35 * 4\)
\(x = 55\)
Alternatively, using a higher level of logic and reduced math: The mean of all males is 35. The mean of all employees is 39 (this does not mean the mean of all females is 43 because the number of females is not the same as that of males). This difference of 4 would equate to the same difference from the mean female score (let's say y). The weighted difference for males is 4 * 40. But we have 10 female employees, so 4 * 40 = 10 * x where x is the additional female score. It turns out to be 16, so the mean female score is 39 + 16 = 55.
Attachments
mathq.png [ 5.92 KiB | Viewed 2690 times ]
In Cytherea Corporation, each employee was given an interper
[#permalink]
23 Nov 2018, 03:51
23 Nov 2018, 03:51
Expert Reply
In Cytherea Corporation, each employee was given an interpersonal assessment with a score from 0 to 60. The average score among all male employees was 35, and the average score for all employees was 39. If Cytherea Corporation has 40 male employees and 10 female employees, what was the average score among all female employees?
A. 40
B. 43
C. 47
D. 51
E. 55
A. 40
B. 43
C. 47
D. 51
E. 55
