GreenlightTestPrep wrote:
Carcass wrote:
If \(xyz < 0\) and \(z < 0\), then which of the following must be true?
A. \(xy=1\)
B. \(xy<1\)
C. \(xy>-z\)
D. \(zy<z\)
E. \(xy>0\)
Kudos for the right answer and explanation
One approach....
Given: xyz is
NEGATIVE and z is
NEGATIVEWe know that
xyz = (xy)(z)Replace values to get:
NEGATIVE = (xy)(
NEGATIVE)
From this we can conclude that (xy) is POSITIVE
Answer: E
Cheers,
Brent
Hi Brent
GreenlightTestPrep, isn't C \(xy>-z\) > is positive > negative always ? Thanks Brent