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Re: Two parking lots can hold a total of 115 cars. The Green lot [#permalink]
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Explanation

Let g = the number of cars that the Green lot can hold. Let r = the number of cars that the Red lot can hold

The first two sentences can be translated into two equations:

\(g + r = 115\)

\(g = r - 35\)

The question asks for r, so substitute (r – 35) for g in the first equation:

\((r - 35) + r = 115\)

\(2r - 35 = 115\)

\(2r = 150\)

\(r = 75\)

Hence option D is correct!
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Re: Two parking lots can hold a total of 115 cars. The Green lot [#permalink]
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sandy wrote:
Two parking lots can hold a total of 115 cars. The Green lot can hold 35 fewer cars than the Red lot. How many cars can the Red lot hold?

(A) 35
(B) 40
(C) 70
(D) 75
(E) 80


We can let n = the number of cars the Red lot can hold and create the equation:

n + n - 35 = 115

2n = 150

n = 75

Answer: D
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