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The “aspect ratio” of a computer monitor is the ratio of the
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14 Jun 2018, 14:11
14 Jun 2018, 14:11
Expert Reply
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A
B
C
D
E
Question Stats:
53% (01:01) correct
46% (01:02) wrong based on 52 sessions
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The “aspect ratio” of a computer monitor is the ratio of the monitor’s width to its height. If a particular monitor has an aspect ratio of 16 : 9, and a perimeter of 100 inches, how many inches wide is the monitor?
(A) 18
(B) 25
(C) 32
(D) 36
(E) 64
(A) 18
(B) 25
(C) 32
(D) 36
(E) 64
Re: The “aspect ratio” of a computer monitor is the ratio of the
[#permalink]
05 Jul 2018, 01:44
05 Jul 2018, 01:44
Expert Reply
Explanation
Rather than assigning separate variables to the width and height, define them both in terms of the same unknown multiplier, based on the ratio given:
Width = 16m
Height = 9m
Remember that the question asks for the width, so answer for 16m, not for m!
The perimeter of a rectangle is equal to 2(length + width), or in this case 2(width + height):
100=2×(16m+9m)
100=50m
m=2
16m=32
An alternative method depends on the same underlying logic, but forgoes the algebra. Suppose the dimensions were 16 inches and 9 inches. This would yield a perimeter of 50 inches. Double the width and height to double the perimeter.
Hence option C is correct!
Rather than assigning separate variables to the width and height, define them both in terms of the same unknown multiplier, based on the ratio given:
Width = 16m
Height = 9m
Remember that the question asks for the width, so answer for 16m, not for m!
The perimeter of a rectangle is equal to 2(length + width), or in this case 2(width + height):
100=2×(16m+9m)
100=50m
m=2
16m=32
An alternative method depends on the same underlying logic, but forgoes the algebra. Suppose the dimensions were 16 inches and 9 inches. This would yield a perimeter of 50 inches. Double the width and height to double the perimeter.
Hence option C is correct!
gmatclubot
Re: The “aspect ratio” of a computer monitor is the ratio of the [#permalink]
05 Jul 2018, 01:44
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