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If 2 of the number of women attending a certain dance is equ
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31 Jul 2019, 02:54
31 Jul 2019, 02:54
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Question Stats:
65% (01:27) correct
34% (00:41) wrong based on 32 sessions
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If \(\frac{2}{3}\) of the number of women attending a certain dance is equal to \(\frac{1}{2}\) the number of men attending, what fraction of those attending are women?
(A) \(\frac{2}{5}\)
(B) \(\frac{3}{7}\)
(C) \(\frac{5}{7}\)
(D) \(\frac{3}{4}\)
(E) \(\frac{5}{6}\)
(A) \(\frac{2}{5}\)
(B) \(\frac{3}{7}\)
(C) \(\frac{5}{7}\)
(D) \(\frac{3}{4}\)
(E) \(\frac{5}{6}\)
Re: If 2 of the number of women attending a certain dance is equ
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31 Jul 2019, 15:20
31 Jul 2019, 15:20
1
We need an equation for total, first. Let's say the fraction that are women plus the fraction that are men is 1.
W+M=1
Now let's get rid of the men.
\(\frac{2}{3} W = \frac{1}{2} M\)
\(\frac{4}{3}\)W=M
So,
W+\(\frac{4}{3}\)W=1
\(\frac{3}{3}\)W + \(\frac{4}{3}\)W=1
\(\frac{7}{3}\)W=1
Isolate W to get \(\frac{3}{7}\)
W+M=1
Now let's get rid of the men.
\(\frac{2}{3} W = \frac{1}{2} M\)
\(\frac{4}{3}\)W=M
So,
W+\(\frac{4}{3}\)W=1
\(\frac{3}{3}\)W + \(\frac{4}{3}\)W=1
\(\frac{7}{3}\)W=1
Isolate W to get \(\frac{3}{7}\)
Re: If 2 of the number of women attending a certain dance is equ
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21 Sep 2019, 06:44
21 Sep 2019, 06:44
Use smart number , such as 6
