As speed and time are inversely proportional when distance is constant (fixed), if the speed becomes $$\frac{6}{7}$$ th of the normal speed, the time would become $$\frac{7}{6}$$ th of the normal time.

Let the normal time be ' $$t$$ ' minutes, so after the reduction/change in speed, the time changes to $$\frac{7}{6} \mathrm{t}$$.

Finally as we know that with reduced speed Chris takes 12 minutes more to reach his destination, we get $$\frac{7}{6} \mathrm{t}-\mathrm{t}=12 \Rightarrow \mathrm{t}=72$$

Hence the normal time that Chris takes to reach his destination is 72 minutes, so the answer is (C).