As speed and time are inversely proportional when distance is constant (fixed), if the speed becomes $\(\frac{6}{7}\)$ th of the normal speed, the time would become $\(\frac{7}{6}\)$ th of the normal time.

Let the normal time be ' $\(t\)$ ' minutes, so after the reduction/change in speed, the time changes to $\(\frac{7}{6} \mathrm{t}\)$.

Finally as we know that with reduced speed Chris takes 12 minutes more to reach his destination, we get $\(\frac{7}{6} \mathrm{t}-\mathrm{t}=12 \Rightarrow \mathrm{t}=72\)$

Hence the normal time that Chris takes to reach his destination is 72 minutes, so the answer is (C).