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Water runs into a cylindrical cistern at the rate of
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22 Dec 2024, 22:41
22 Dec 2024, 22:41
Expert Reply
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Question Stats:
66% (01:52) correct
33% (03:13) wrong based on 6 sessions
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Water runs into a cylindrical cistern at the rate of \(924 m^3\) per minute. If the water level rises to 0.1 meter in one second, what is the radius of the cistern?
A. 5
B. 7
C. 8
D. 10
E. 11
A. 5
B. 7
C. 8
D. 10
E. 11
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Water runs into a cylindrical cistern at the rate of
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02 Feb 2025, 06:58
02 Feb 2025, 06:58
Expert Reply
OE
Let the radius of the cistern be ' $r$ ' meter.
If the water rises 0.1 meter in one second, it would rise $\(0.1 \times 60=6\)$ meter in one minute.
We know that water runs in the cylindrical cistern at the rate of $\(924 \mathrm{~m}^3\)$ per minute, so we get the volume of the cylindrical cistern as $\(\pi r^2 h=924 \mathrm{~m}^3\)$ i.e.
$\(\frac{22}{7} \times r^2 \times 6=924\)\( \Rightarrow r=\sqrt{924 \times \frac{7}{22} \times \frac{1}{6}\)\(=7\)$ meter
Hence the answer is (B).
Let the radius of the cistern be ' $r$ ' meter.
If the water rises 0.1 meter in one second, it would rise $\(0.1 \times 60=6\)$ meter in one minute.
We know that water runs in the cylindrical cistern at the rate of $\(924 \mathrm{~m}^3\)$ per minute, so we get the volume of the cylindrical cistern as $\(\pi r^2 h=924 \mathrm{~m}^3\)$ i.e.
$\(\frac{22}{7} \times r^2 \times 6=924\)\( \Rightarrow r=\sqrt{924 \times \frac{7}{22} \times \frac{1}{6}\)\(=7\)$ meter
Hence the answer is (B).
gmatclubot
Water runs into a cylindrical cistern at the rate of [#permalink]
02 Feb 2025, 06:58
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