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Waugh jogged to a restaurant at x miles per hour, and jogged
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30 Apr 2019, 00:18
30 Apr 2019, 00:18
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62% (01:30) correct
37% (01:39) wrong based on 27 sessions
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Waugh jogged to a restaurant at x miles per hour, and jogged back home along the same route at y miles per hour. He took 30 minutes for the whole trip. If the restaurant is 2 miles from home, what is the average speed in miles per hour at which he jogged for the whole trip?
(A) 0.13
(B) 0.5
(C) 2
(D) 4
(E) 8
(A) 0.13
(B) 0.5
(C) 2
(D) 4
(E) 8
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Re: Waugh jogged to a restaurant at x miles per hour, and jogged
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12 May 2020, 22:55
12 May 2020, 22:55
1
Carcass wrote:
Waugh jogged to a restaurant at x miles per hour, and jogged back home along the same route at y miles per hour. He took 30 minutes for the whole trip. If the restaurant is 2 miles from home, what is the average speed in miles per hour at which he jogged for the whole trip?
(A) 0.13
(B) 0.5
(C) 2
(D) 4
(E) 8
(A) 0.13
(B) 0.5
(C) 2
(D) 4
(E) 8
Distance = 2 miles
Total time = 30 min = 1/2 hr
=> Average speed = total distance / total time = (2+2)/(1/2) = 8 miles per hour
(Note: x and y are not necessary)
Answer E
Re: Waugh jogged to a restaurant at x miles per hour, and jogged
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09 Jun 2021, 08:29
09 Jun 2021, 08:29
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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