Carcass wrote:
What is the product of all roots of the equation \((x+1)^2=|x+1|\)?
\(A. -2\)
\(B. -1\)
\(C. 0\)
\(D. 1\)
\(E. 2\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITIONGRE - Math BookThere are 3 steps to solving equations involving ABSOLUTE VALUE:
1. Apply the rule that says:
If |x| = k, then x = k and/or x = -k2. Solve the resulting equations
3. Plug solutions into original equation to check for extraneous roots
Given: (x + 1)² = | x + 1|
Apply rule to get two equations:
(x + 1)² = x + 1 and
-(x + 1)² = x + 1Take:
(x + 1)² = x + 1Expand and simplify left side: x² + 2x + 1 = x + 1
Set this quadratic equation to equal zero: x² + x = 0
Factor to get: x(x + 1) = 0
So,
x = 0 and
x = -1 are two solutions (aka roots) of the original equation
When we test these two solutions, we find that they BOTH work.
IMPORTANT: At this point, we COULD solve
-(x + 1)² = x + 1 for x also. HOWEVER, doing so would be a
waste of time since the questions asks us to find the PRODUCT of all possible solutions.
Since
x = 0 is one of the solutions, we can be sure that
the product will be 0Answer: C