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What is the product of the factors of twice the sum of the
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18 Mar 2018, 06:32
18 Mar 2018, 06:32
Expert Reply
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Question Stats:
91% (01:04) correct
8% (00:00) wrong based on 12 sessions
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What is the product of the factors of twice the sum of the roots of the equation \(2x^2 - 4x - 6 = 0\)?
Drill 2
Question: 3
Page: 497
Question: 3
Page: 497
Show: :: OA
8
Re: What is the product of the factors of twice the sum of the
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18 Mar 2018, 06:55
18 Mar 2018, 06:55
1
Expert Reply
Explanation
First, factor the quadratic: (2x + 2)(x – 3) = 0.
Next, solve for each solution (root). If 2x + 2 = 0, then x = –1. If x – 3 = 0, then x = 3.
The sum of the roots is 2, and twice their sum is 4.
The factors of 4 are 1, 2, 4, and the product of those factors is 8, the final answer.
First, factor the quadratic: (2x + 2)(x – 3) = 0.
Next, solve for each solution (root). If 2x + 2 = 0, then x = –1. If x – 3 = 0, then x = 3.
The sum of the roots is 2, and twice their sum is 4.
The factors of 4 are 1, 2, 4, and the product of those factors is 8, the final answer.
Re: What is the product of the factors of twice the sum of the
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30 Mar 2018, 02:24
30 Mar 2018, 02:24
To simplify the equation further, 2 can be taken common so that factoring gets easy. Arthematic question with words instead of symbols is confusing!!
