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What is the remainder when (92n + 3)(5n ) is divided by 10, where n is
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12 Aug 2024, 23:34
12 Aug 2024, 23:34
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Question Stats:
56% (01:26) correct
43% (01:37) wrong based on 23 sessions
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What is the remainder when \((9^{2n + 3})(5^n)\) is divided by 10, where \(n\) is a positive integer?
A. 1
B. 2
C. 4
D. 5
E. 8
A. 1
B. 2
C. 4
D. 5
E. 8
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
Re: What is the remainder when (92n + 3)(5n ) is divided by 10, where n is
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22 Sep 2024, 17:11
22 Sep 2024, 17:11
1
The cycle of unit digits of 9 is 9, 1 (9^1 = 9, 9^2 = 81, 9^3 = 729 and so on)
The cycle of unit digits of 9 is 5 (5^1 = 5, 5^2 = 25..)
Multiply cycle of unit digits of 9 and 5 together, 9*5 = 45, 1*5 = 5
We see that unit digits is always 5, so remainder is 5 when the number is divided by 10
The cycle of unit digits of 9 is 5 (5^1 = 5, 5^2 = 25..)
Multiply cycle of unit digits of 9 and 5 together, 9*5 = 45, 1*5 = 5
We see that unit digits is always 5, so remainder is 5 when the number is divided by 10
Re: What is the remainder when (92n + 3)(5n ) is divided by 10, where n is
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24 Sep 2024, 11:50
24 Sep 2024, 11:50
1
The remainder when a number is divided by 10 is always the unit digit. Now when you raise 5 to any power of positive integer, unit digit is 5. 5 multiplied by any number leaves a remainder of either 0 or 5 as unit digit. Since there is no zero in the option, answer is 5.
