Carcass wrote:
What is the sixth term in a sequence in which the \(n\)th term is \(n( n − 1)^2\)?
A. 42
B. 150
C. 900
D. 1,225
E. 2,592
We're given a direct formula for calculating every term.
That is....
term_n = n( n − 1)²For example:
term_
1 =
1(
1 − 1)² = 1(0)² = 0
term_
2 =
2(
2 − 1)² = 2(1)² = 2
term_
3 =
3(
3 − 1)² = 3(2)² = 12
...etc
So, term_
6 =
6(
6 − 1)² = 6(5)² = 150
Answer: B
Cheers,
Brent