Re: What is the y-intercept of the line shown in the above figure? 7 8
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22 Dec 2024, 13:02
Equation of a line joining two points $\(\left(x_1, x_2\right) \&\left(y_1, y_2\right)\)$ is $\(\left(y-y_1\right)=\frac{y_2-y_1}{x_2-x_1}\left(x-x_1\right)\)$
Using the above formula, the equation of line joining points $\((3,6) \&(6,4)\)$ is $\((y-4)=\frac{6-4}{3-6}(x-6)\)$ which when simplified we get $\(2 x+3 y=24\)$
The $\(y\)$-intercept is a value of $\(y\)$ when $\(x\)$ is zero or we can say $\(y\)$-intercept is a point where line cuts y -axis.
So, the $\(y\)$-intercept of the line $\(2 x+3 y=24\)$ is $\(2 \times 0+3 y=24 \Rightarrow y=8\)$
Hence the answer is (B).