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What of the following is the closest to the estimated valu
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26 Jun 2021, 02:49
26 Jun 2021, 02:49
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\(1 < a < b < c < 2\)
What of the following is the closest to the estimated value of \(a+b*10^6+c*10^{12}?\)
A. \(b*10^9\)
B. \(c*10^{12}\)
C. \((a+b+c)*10^6\)
D. \( (b+c-a)*10^{18}\)
E. \((a+b)*10^{12}\)
What of the following is the closest to the estimated value of \(a+b*10^6+c*10^{12}?\)
A. \(b*10^9\)
B. \(c*10^{12}\)
C. \((a+b+c)*10^6\)
D. \( (b+c-a)*10^{18}\)
E. \((a+b)*10^{12}\)
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Re: What of the following is the closest to the estimated valu
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27 Jun 2021, 02:28
27 Jun 2021, 02:28
1
kumarneupane4344 wrote:
\(1 < a < b < c < 2\)
What of the following is the closest to the estimated value of \(a+b*10^6+c*10^{12}?\)
A. \(b*10^9\)
B. \(c*10^{12}\)
C. \((a+b+c)*10^6\)
D. \( (b+c-a)*10^{18}\)
E. \((a+b)*10^{12}\)
What of the following is the closest to the estimated value of \(a+b*10^6+c*10^{12}?\)
A. \(b*10^9\)
B. \(c*10^{12}\)
C. \((a+b+c)*10^6\)
D. \( (b+c-a)*10^{18}\)
E. \((a+b)*10^{12}\)
Since, \(c(10^{12}) >>>> b(10^6) >>> a\)
\(b(10^6)\) and \(a\) are negligible as compared to \(c(10^{12})\)
Therefore, \(a+b*10^6+c*10^{12} ≈ c(10^{12})\)
Hence, option B
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Re: What of the following is the closest to the estimated valu
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16 Jul 2021, 10:03
16 Jul 2021, 10:03
1
\(a+b*10^6+c*10^{12}\) has three terms
a where 1<a<2
\(b*10^6\) where 1<b<2
\(c*10^{12}\) where 1<c<2
Now, compared to \(c*10^{12}\) a is negligible so we can ignore that.
Even \(b*10^6\) is small as compared to \(c*10^{12}\), but let's keep it for now and let's look at the answer choices
A. \(b*10^9\) this will be way less than \(b*10^{12}\) so will be way less than too \(c*10^{12}\)
=> NOT the closes to \(a+b*10^6+c*10^{12}\)
B. \(c*10^{12}\)
Let's keep this as this is close to \(b*10^6+c*10^{12}\)
C. \((a+b+c)*10^6\)
Now, even when we approximate a and b to be equal to c then the maximum value of this can still be
3c*10^6 which is way less than \(b*10^6+c*10^{12}\)
D. \( (b+c-a)*10^{18}\)
Now this gets multiplied with \(10^{18}\) which will become too big as compared to \(b*10^6+c*10^{12}\)
E. \((a+b)*10^{12}\)[/quote]
Now, lets assume a=1.1, b=1.2 and c=1.9
a+b = 2.3
=> \((a+b)*10^{12}\) = \(2.3*10^{12}\) will become too big as compared to \(1.1*10^6+1.9*10^{12}\)
So, answer will be B
Hope it helps!
a where 1<a<2
\(b*10^6\) where 1<b<2
\(c*10^{12}\) where 1<c<2
Now, compared to \(c*10^{12}\) a is negligible so we can ignore that.
Even \(b*10^6\) is small as compared to \(c*10^{12}\), but let's keep it for now and let's look at the answer choices
A. \(b*10^9\) this will be way less than \(b*10^{12}\) so will be way less than too \(c*10^{12}\)
=> NOT the closes to \(a+b*10^6+c*10^{12}\)
B. \(c*10^{12}\)
Let's keep this as this is close to \(b*10^6+c*10^{12}\)
C. \((a+b+c)*10^6\)
Now, even when we approximate a and b to be equal to c then the maximum value of this can still be
3c*10^6 which is way less than \(b*10^6+c*10^{12}\)
D. \( (b+c-a)*10^{18}\)
Now this gets multiplied with \(10^{18}\) which will become too big as compared to \(b*10^6+c*10^{12}\)
E. \((a+b)*10^{12}\)[/quote]
Now, lets assume a=1.1, b=1.2 and c=1.9
a+b = 2.3
=> \((a+b)*10^{12}\) = \(2.3*10^{12}\) will become too big as compared to \(1.1*10^6+1.9*10^{12}\)
So, answer will be B
Hope it helps!
