GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
When positive integer k is divided by 6 the remainder is 3. Which of t
[#permalink]
12 Jul 2021, 05:47
12 Jul 2021, 05:47
Expert Reply
1
Bookmarks
00:00
Question Stats:
78% (01:27) correct
21% (02:12) wrong based on 23 sessions
Hide Show timer Statistics
When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?
a. k + 1
b. k -11
c. 4k + 2
d. (k-3)/3 +2
e. k/3
a. k + 1
b. k -11
c. 4k + 2
d. (k-3)/3 +2
e. k/3
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: When positive integer k is divided by 6 the remainder is 3. Which of t
[#permalink]
12 Jul 2021, 08:21
12 Jul 2021, 08:21
1
1
Bookmarks
Carcass wrote:
When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?
a. k + 1
b. k -11
c. 4k + 2
d. (k-3)/3 +2
e. k/3
a. k + 1
b. k -11
c. 4k + 2
d. (k-3)/3 +2
e. k/3
approach is to TEST values.
When positive integer k is divided by 6 the remainder is 3
So, k could equal 3, 9, 15, 21, etc
let's TEST k = 3
a. 3 + 1 = 4 (EVEN)
b. 3 -11 = -8 (EVEN)
c. 4(3) + 2 = 14 (EVEN)
d. (3-3)/3 +2 = 2 (EVEN)
At this point, we can already see the answer must be E.
Let's check E for "fun"
e. 3/3 = 1 (ODD)
Great!
Answer: E
Cheers,
Brent
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1115
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Re: When positive integer k is divided by 6 the remainder is 3. Which of t
[#permalink]
05 Sep 2022, 09:42
05 Sep 2022, 09:42
1
When positive integer k is divided by 6 the remainder is 3
Theory: Dividend = Divisor*Quotient + Remainder
k -> Dividend
6 -> Divisor
a -> Quotient (Assume)
3 -> Remainders
=> k = 6*a + 3 = 6a + 3
Which of the following CANNOT be an even integer
Let's take each option and evaluate if it CANNOT be an even integer
a. k + 1
k + 1 = 6a + 3 + 1 = 6a + 4 => EVEN
b. k -11
k - 11 = 6a + 3 - 11 = 6a - 8 => EVEN
c. 4k + 2
4k + 2 = 4*(6a + 3) + 2 = 24a + 20 => EVEN
d. \(\frac{(k-3)}{3}\) + 2
\(\frac{(k-3)}{3}\) + 2 = \(\frac{(6a + 3 -3)}{3}\) + 2 = 2a + 2 => EVEN
e. \(\frac{k}{3}\)
\(\frac{k}{3}\) = \(\frac{6a + 3}{3}\) = 2a + 1 => ODD
So, Answer will be E
Hope it helps!
Watch the following video to learn the Basics of Remainders
Theory: Dividend = Divisor*Quotient + Remainder
k -> Dividend
6 -> Divisor
a -> Quotient (Assume)
3 -> Remainders
=> k = 6*a + 3 = 6a + 3
Which of the following CANNOT be an even integer
Let's take each option and evaluate if it CANNOT be an even integer
a. k + 1
k + 1 = 6a + 3 + 1 = 6a + 4 => EVEN
b. k -11
k - 11 = 6a + 3 - 11 = 6a - 8 => EVEN
c. 4k + 2
4k + 2 = 4*(6a + 3) + 2 = 24a + 20 => EVEN
d. \(\frac{(k-3)}{3}\) + 2
\(\frac{(k-3)}{3}\) + 2 = \(\frac{(6a + 3 -3)}{3}\) + 2 = 2a + 2 => EVEN
e. \(\frac{k}{3}\)
\(\frac{k}{3}\) = \(\frac{6a + 3}{3}\) = 2a + 1 => ODD
So, Answer will be E
Hope it helps!
Watch the following video to learn the Basics of Remainders
