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Re: Which is greater? [#permalink]
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wongpcla wrote:
Image


Image


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


Bunuel please correct how wrong I am,
OB=2, OC=2, BC=3 ; OA=2, OC=2, AC=3 similar triangle AOC~BOC
AC*AC = 3*3 = 9


No. Triangles AOC and BOC are not similar. Only two side there are equal. To find AC you shoul recall the following property:

A right triangle inscribed in a circle must have its hypotenuse as the diameter of the circle (the reverse is also true: if the diameter of a circle is also the triangle’s side, then that triangle is a right triangle).

Thus, ABC is a right tringle right angled at C. Now, using Pythagoras theorem:
AC^2 + BC^2 = AB^2;
AC^2 + 9 = 16;
\(AC =\sqrt{7}\)

The area of the square \(side^2=(\sqrt{7})^2=7\).

The two quantities are equal

Answer: C.
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Re: Which is greater? [#permalink]
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it should be D, because it is not mentioned the AB is the diameter of circle
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Re: Which is greater? [#permalink]
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Please see the explanation above. They are there for aa specific reason
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Re: Which is greater? [#permalink]
I do not get that how we have assumed AB to be the Diameter ?
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Re: Which is greater? [#permalink]
raghavtandonlfc wrote:
I do not get that how we have assumed AB to be the Diameter ?


Formal definition: In geometry, a diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints lie on the circle

The question tells us that the point O is the center of the circle.
Since AB passes through point O, it must be a diameter.
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Re: Which is greater? [#permalink]
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