------CONCEPT----------
A is always positive
B is always negative

Hence A > B

The logic used in the above solutions are perfect (and they're how I'd also solve it), but here's another approach that involves matching operations

Given:
Quantity A: \(5y^2\)
Quantity B: -\(\frac{y^2}{7}\)

Since \(y^2\) must be POSITIVE, we can safely divide both quantities by \(y^2\) to get:
Quantity A: \(5\)
Quantity B: -\(\frac{1}{7}\)

Answer: A

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A is greater than B thus A

lets consider y = 1, 1/2, -1, -1/2

Y =1 --> A> B
Y = 1/2--> A>B
Y = -1 --> A> B
Y = -1/2 --> A> B
Thus A
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