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x<0<y+z
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30 Aug 2016, 09:51
30 Aug 2016, 09:51
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79% (00:58) correct
20% (01:05) wrong based on 34 sessions
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\(x<0<y+z\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
(y+z)/x |
y/z |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: x<0<y+z
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31 Aug 2016, 10:36
31 Aug 2016, 10:36
1
Sonalika42 wrote:
x<0<y+z
Quantity A |
Quantity B |
(y+z)/x |
y/z |
Given: x < 0 < y+z
This tells us that x is NEGATIVE and y+z is POSITIVE
So, we get:
Quantity A: (y+z)/x = POSITIVE/NEGATIVE
Quantity B: y/z
Simplify to get:
Quantity A: NEGATIVE
Quantity B: y/z
Does this help? Not really. We know that 0 < y+z, but we don't know anything about the individual values of y and z.
At this point, I might start TESTING VALUES
We need values that satisfy the given info: x < 0 < y+z
How about x = -1, y = 1 and z = 1. We get:
Quantity A: (1+1)/(-1) = -2
Quantity B: 1/1 = 1
Quantity B is greater.
So, the correct answer is either B or D.
Try some more values. How about x = -1, y = 5 and z = -1. We get:
Quantity A: (5 + -1)/-1 = -4
Quantity B: 5/-1 = -5
Quantity A is greater.
DONE!
Answer:
Show: ::
D
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Re: x<0<y+z
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13 Dec 2021, 23:54
13 Dec 2021, 23:54
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