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x^-1-y^-1
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12 Jun 2024, 00:06
12 Jun 2024, 00:06
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Question Stats:
76% (01:06) correct
23% (01:11) wrong based on 17 sessions
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\(x^{-1}-y^{-1}=(xy)^{-1}\)
\(xy \neq\) zero
\(xy \neq\) zero
Quantity A |
Quantity B |
x |
y |
Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2024 Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
Re: x^-1-y^-1
[#permalink]
12 Jun 2024, 14:39
12 Jun 2024, 14:39
Carcass wrote:
\(x^{-1}-y^{-1}=(xy)^{-1}\)
\(xy \neq\) zero
\(xy \neq\) zero
Quantity A |
Quantity B |
x |
y |
Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2024 Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
Howw??
Re: x^-1-y^-1
[#permalink]
13 Jun 2024, 00:38
13 Jun 2024, 00:38
Expert Reply
Please make a review how to deal with powers and roots
https://gre.myprepclub.com/forum/gre-ma ... 24948.html
https://gre.myprepclub.com/forum/how-to ... ml#p104869
This \(x^{-1}-y^{-1}=(xy)^{-1}\)
will become
\(\frac{1}{x}-\frac{1}{y}=\frac{1}{xy}\)
\(\frac{y-x}{xy}=\frac{1}{xy}\)
Solve and we have that
\(y=x+1\)
QA is just x
QB is the result of x+1
B>A
https://gre.myprepclub.com/forum/gre-ma ... 24948.html
https://gre.myprepclub.com/forum/how-to ... ml#p104869
This \(x^{-1}-y^{-1}=(xy)^{-1}\)
will become
\(\frac{1}{x}-\frac{1}{y}=\frac{1}{xy}\)
\(\frac{y-x}{xy}=\frac{1}{xy}\)
Solve and we have that
\(y=x+1\)
QA is just x
QB is the result of x+1
B>A
